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/* Copyright 2023 Mario Finelli
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
//! Advent of Code 2023 Day 1: <https://adventofcode.com/2023/day/1>
//!
//! A rather challenging problem for day one! Part one was very straightforward
//! but it took me a while to figure out how to solve part two. My initial
//! implementation used a regex to try and account for both numbers and the
//! number-words but there were many edge cases and after a few wrong
//! submission attempts I gave up and got the trick from the subreddit. The
//! trick is rather simple: just replace the number words with the number
//! wrapped by its number word (e.g., "one" becomes "one1one"). This lets us
//! also account for multiple numbers encoded into a single word (see example
//! below in the function description).
/// The solution the day one challenge.
///
/// We take the input as a string and the part that we're solving (in part `2`
/// we treat number-words as their number equivalents). We loop through each
/// line and if we're in part two then we replace the number-words with their
/// number equivalents (we wrap the number with its number-word so that if
/// there are two words together we can account for both of them e.g., eightwo
/// should provide both an 8 and a 2). Then we check each character from the
/// input until we find a number match for the first digit and then we reverse
/// the input and check again to find the second digit. We put them together,
/// parse the result as an integer and add it to our total.
///
/// # Example
/// ```rust
/// # use aoc::y23d01::y23d01;
/// // probably read this from the input file...
/// let input = "one1twothree4\n24\nthree4five";
/// assert_eq!(y23d01(input, 1), 82);
/// assert_eq!(y23d01(input, 2), 73);
/// ```
pub fn y23d01(input: &str, part: u32) -> u32 {
let numbers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'];
let mut total = 0;
for line in input.lines() {
let mut first: Option<char> = None;
let mut last: Option<char> = None;
let search = if part == 2 {
line.replace("zero", "zero0zero")
.replace("one", "one1one")
.replace("two", "two2two")
.replace("three", "three3three")
.replace("four", "four4four")
.replace("five", "five5five")
.replace("six", "six6six")
.replace("seven", "seven7seven")
.replace("eight", "eight8eight")
.replace("nine", "nine9nine")
} else {
line.to_string()
};
for c in search.chars() {
if numbers.contains(&c) {
first = Some(c);
break;
}
}
for c in search.chars().rev() {
if numbers.contains(&c) {
last = Some(c);
break;
}
}
let number = format!("{}{}", first.unwrap(), last.unwrap());
total += number.parse::<u32>().unwrap();
}
total
}
#[cfg(test)]
mod tests {
use super::*;
use std::fs;
#[test]
fn it_works() {
let mut input = "1abc2\npqr3stu8vwx\na1b2c3d4e5f\ntreb7uchet\n";
assert_eq!(y23d01(input, 1), 142);
input = concat!(
"two1nine\n",
"eightwothree\n",
"abcone2threexyz\n",
"xtwone3four\n",
"4nineeightseven2\n",
"zoneight234\n",
"7pqrstsixteen\n",
);
assert_eq!(y23d01(input, 2), 281);
}
#[test]
fn the_solution() {
let contents = fs::read_to_string("input/2023/day01.txt").unwrap();
assert_eq!(y23d01(&contents, 1), 55712);
assert_eq!(y23d01(&contents, 2), 55413);
}
}